Respuesta :
Answer:
[tex]y=4(x)^2[/tex]
Step-by-step explanation:
Focus =(h,k+p)
Directrix= y=k-p
Focus given is : (0,1)
And directrix given is : y=-1
(h,k+p) =(0,1)
On comparing the values we get
h=0 and k+p=1
y=k-p= -1
Hence, we gave two equations
k+p=1 and k-p= -1
Substitute p= 1-k in k-p= -1 we get:
k-(1-k) = -1
k-1+k= -1
k=0
Now, we get
h=0 and k=0
And put k=0 in p = 1-k
We get p=1
We have general equation of parabola
[tex](y-k)=4p(x-h)^2[/tex]
[tex](y-0)=4(1)(x-0)^2[/tex]
[tex]y=4(x)^2[/tex]
Hence, the required equation is :
[tex]y=4(x)^2[/tex]
Answer:
warning, it is NOT f(x)= 4x^2, I got a 0 on the question for putting in that answer. my best guess is that they forgot the negative sign? so I would try the f(x)= -4x^2 option instead, hope it works out
