Respuesta :
that is basically the slope
that would be
[tex]\frac{f(0)-f(3)}{0-3}[/tex] or [tex]\frac{f(3)-f(0)}{3-0}[/tex]
both will yeild the averge rate of change
that would be
[tex]\frac{f(0)-f(3)}{0-3}[/tex] or [tex]\frac{f(3)-f(0)}{3-0}[/tex]
both will yeild the averge rate of change
[f(3) - f(0)]/(3-0)
[f(3) - f(0)]/3
What is the average rate of change of f over the interval 0 3?
The average rate of change of a function, f on the interval [0,3] is f(3)−f(0)3−0 Which in this case, is (81−15)−(0)3−0=663=22.
What is the average rate of change on the interval 0 4 and on the interval 6 10?
Answer. The average rate of change on the interval [6,10]:10−410−6=64=32kgallom/h A possible explanation: Between 0 and 4 hours, residents consumed water in the tank at the average rate of 2k gallons per hour.
Learn more about a change of f(x) over the interval [0,3] at
https://brainly.com/question/10945539
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