Refer to the diagram shown below.
u = 20 m/s, the horiontal launch velocity
v = 0, initial vertical velocity
Assume that wind resistance may be ignored.
The time, t, of the flight is given by
(1/2)*(9.8 m/s²)*t² = (100 m)
t² = 100/4.9 = 20.4082
t = 4.5175 s
Th horizontal distance traveled is
d = (20 m/s)*(4.5175 s) = 90.35 m
Answer: B
The projectile hits the ground at approximately 90 m from the base of the cliff.
