Respuesta :
Let the radius of circle a be R, then the radius of circle b is 3R.
The circumference of circle b is 2π*(radius b)=2π*3R= 6πR.
The circumference of circle a is 2π*(radius a)=2π*R=2πR.
This means that one complete revolution of circle a covers 2πR distance. Since there is a total 6πR distance in circle b:
Circle a revolves in total 6πR/2πR=3 many times.
Answer: 3
The circumference of circle b is 2π*(radius b)=2π*3R= 6πR.
The circumference of circle a is 2π*(radius a)=2π*R=2πR.
This means that one complete revolution of circle a covers 2πR distance. Since there is a total 6πR distance in circle b:
Circle a revolves in total 6πR/2πR=3 many times.
Answer: 3
Let r = radius of circle a.
Then the radius of circle b is 3r.
One revolution around circle b is 2π*(3r) = 6πr
One revolution of circle a is a distance of 2πr.
Therefore when circle a rolls one trip around circle b, it will make
(6πr)/(2πr) = 3 revolutions.
Answer: Circle a will revolve 3 times
Then the radius of circle b is 3r.
One revolution around circle b is 2π*(3r) = 6πr
One revolution of circle a is a distance of 2πr.
Therefore when circle a rolls one trip around circle b, it will make
(6πr)/(2πr) = 3 revolutions.
Answer: Circle a will revolve 3 times
