Ms. jamison plans to invest $3,800 in two accounts for one year. the first account earns a yearly interest of 3.5%. the second account earns a yearly interest of 6%. how much money does ms. jamison need to invest in the second account in order to earn $188 in interest from both accounts?

Respuesta :

0.035x+0.06 (3800-x)=188
Solve for x
0.035x+228-0.06x=188
0.035x-0.06x=188-228
-0.025x=-40
X=40/0.025
X=1600. Invested at 3.5%

3800-1600=2200 invested at 6%

Answer:

2,200

Explanation: