Answer:
Step-by-step explanation:
f(x) =15x
Given function is defined for all values of x therefore its domain is all real numbers.
f(x) =[tex]\sqrt{x}[/tex]
we know that value in the square is defined only for non negative numbers
therefore domain of this function is set of all non negative real numbers
f(x) =[tex]\frac{1}{x-2}[/tex]
here we can see that function is not defined when x =2 and it is defined for rest of the values
therefore here function domain is set of all real numbers except 2 .
f(x) =[tex]\frac{1}{\sqrt{x-2}}[/tex]
here we can see that function is not defined for x=2 and when value in the square root is negative.
so domain of this function is all real values greater than 2
that is x>2
