Respuesta :
Answer:
The invalid statement is 4) Segment AP is congruent to segment PQ.
We conclude that 2) Segment RB is congruent to segment CS.
Step-by-step explanation:
Given, line segment AB & CD
Here, P is the midpoint of AB ⇒ AP=PB
& Q is the midpoint of CD ⇒ CQ=QD
It is given that P is point on AB not on CD ∴ there is no relation of point P with line segment CQ.
Hence, the invalid statement is
Segment AP is congruent to segment PQ.
Now, given that R is the midpoint of AP ⇒ AR=RP
& S is the midpoint of QD ⇒ QS=SD
AB≅CD (Given)
[tex]\frac{1}{2} AB[/tex] ≅ [tex]\frac{1}{2} CD[/tex]
PB ≅ CQ (∵from midpoint statements)
∵ PA=QD ⇒ PR=QS
Because PB≅CQ
PB+PR≅CQ+QS
⇒ RB≅CS
Therefore, Segment RB is congruent to segment CS
The invalid statement is
- Segment AP is congruent to segment PQ.
Our conclusion is that:
- Segment RB is congruent to segment CS.
What is a Congruent Segment?
This refers to the segments which are equal in length and can be found by using the midpoints of each segment.
Hence, we can see that based on the line segment AB & CD,
- P is the midpoint of AB ⇒ AP=PB
- Q is the midpoint of CD ⇒ CQ=QD
Because P is point on AB not on CD, therefore there is no relation of point P with line segment CQ.
Therefore, the invalid statement is
- Segment AP is congruent to segment PQ.
Now, to prove congruency,
- PB ≅ CQ (from midpoint statements)
- PA=QD ⇒ PR=QS
Based on the fact that PB≅CQ
PB+PR≅CQ+QS
⇒ RB≅CS
Therefore, Segment RB is congruent to segment CS
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