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Which of the following is true of the location of an angle, 0, whose tangent value is the negative square root of three over three?

PLEASE PLEASE HELP RUNNING OUT OF TIME Which of the following is true of the location of an angle 0 whose tangent value is the negative square root of three ove class=

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akiyama316
[tex]tan \theta = - \frac{\sqrt{3}}{3}[/tex]

tan \theta = - \frac{1}{\sqrt{3}}

We know tan(theta) is negative in 2nd and 4th quadrant.

theta =  150 degrees
means 30 degrees reference angle.

Option A is the answer.

Answer:

Option A

Step-by-step explanation:

We have to find the location of an angle θ, whose tangent value is [tex]\frac{-\sqrt{3}}{3}[/tex]

So it is given that tan θ = [tex]\frac{-\sqrt{3}}{3}[/tex]

                             tan θ = [tex]\frac{-1}{\sqrt{3} }[/tex]

                                   θ = [tex]tan^{-1}(\frac{-1}{\sqrt{3} }[/tex]

If tangent of nay angle θ is negative than θ lies in 2nd and 4th quadrant.

So θ = 30° will lie in 2nd or 4th quadrant.

Option A is the answer.

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