The first one is the only that might give you some trouble. The first thing you do is factor out the [tex] b^{2} [/tex]:
[tex] b^{2} (2 x^{2} +5x+2)[/tex]
and then you have to factor the rest using the quadratic formula. The whole thing factored looks like this, then:
[tex] b^{2} (x+ \frac{1}{2})(x+2) [/tex]
The second one can be factored straight out:
(x-4)(x-4)
Then the third one can be factored by taking roots. Recognize that [tex] x^{2} [/tex] is a perfect square and so is 49:
[tex] x^{2} =49[/tex]
and taking the square root of both sides gives you this:
x = +/- 7
