Data:
M (molarity) = 8.50 M
m (mass) = ? (in grams)
V (volume) = 250 mL → 0.25 L
MM (Molar Mass) of Sodium Hydroxide
Na = 1*23 = 23 amu
O = 1*16 = 16 amu
H = 1*1 = 1 amu
------------------------------------
MM of NaOH = 23+16+1 = 40 g/mol
Formula:
[tex]M = \frac{m}{MM*V} [/tex]
Solving:
[tex]M = \frac{m}{MM*V} [/tex]
[tex]8.50 = \frac{m}{40*0.25} [/tex]
[tex]8.50 = \frac{m}{10} [/tex]
[tex]m = 8.50*10[/tex]
[tex]\boxed{\boxed{m = 85\:g}}\end{array}}\qquad\quad\checkmark[/tex]
Answer:
85 grams
