Data:
M (molarity) = ? (Mol/L)
m (mass) = ? (in grams)
V (volume) = 2 L
MM (Molar Mass) of Potassium Hydroxide (KOH)
K = 1*39 = 39 amu
O = 1*16 = 16 amu
H = 1*1 = 1 amu
------------------------------------
MM of KOH = 39+16+1 = 56 g/mol
***Let's find the mass
Data:
n (number of mols) = 4.5 mols
m (mass) = ? (in grams)
v (volume) = 2 L
Formula:
[tex]n = \frac{m}{V} [/tex]
[tex]4.5 = \frac{m}{2} [/tex]
[tex]m = 4.5*2[/tex]
[tex]\boxed{m = 9.0\:g}[/tex]
***Let's find the molarity:
Formula:
[tex]M = \frac{m}{MM*V} [/tex]
Solving:
[tex]M = \frac{m}{MM*V} [/tex]
[tex]M = \frac{9.0}{56*2} [/tex]
[tex]M = \frac{9.0}{112} [/tex]
[tex]M = 0.0803...\:\to\:\boxed{\boxed{M \approx 0.08\:Mol/L}}\end{array}}\qquad\quad\checkmark[/tex]
