Problem: -[tex]-5 (x + 2) = 0[/tex]
Steps ↓
[tex]Step^1[/tex]: Fix the problem: [tex]-5(x) + -5(2) = 0 [/tex]
[tex]Step^2: -5(2) = 10 [/tex] ← To get that we have to multiply [tex]-5 [/tex] by[tex]2[/tex]
[tex]Step^3: [/tex] change your symbols(addition to subtraction) →[tex]5x - 10 =0 [/tex]
[tex]Step^4: [/tex] Let's [tex]divide[/tex] ( ÷ ) by a negative 5 [tex](-5)[/tex] →[tex] \frac{-5x}{-5} [/tex] & [tex] \frac{10}{-5} [/tex]
[tex] \frac{-5x}{5} = -x \\ \\ \frac{10}{-5} = -2 [/tex]
[tex]Step^5: [/tex] Answer:[tex]x =[/tex] [tex]-2 [/tex]
