check the picture below.
so... a cylinder that has the same "h" and "r" as a cone, will have a volume of
[tex]\bf \textit{volume of a cone}\\\\
V_{cone}=\cfrac{\pi r^2 h}{3}\qquad 3V_{cone}=\boxed{\pi r^2 h}\qquad V_{cone}=242.1\\\\\\ 3V_{cone}=3(242.1)
\\\\\\
\textit{volume of a cylinder}\\\\
V_{cylinder}=\boxed{\pi r^2 h}\implies 3V_{cone}\implies 3(242.1)\implies 726.3[/tex]
