Answer:
Explanation:
To compare the electromotive forces (EMFs) of two cells using a potentiometer, connect the positive terminal of the first cell (Cell A) to the positive terminal of the potentiometer and link the negative terminal of Cell A to the potentiometer's jockey terminal. Connect the negative terminal of the potentiometer to Cell A's negative terminal and join the positive terminal of the potentiometer to the positive terminal of the second cell (Cell B). Adjust the length of the potentiometer wire until the galvanometer reads zero, indicating that the potential difference across the wire equals the EMF of Cell A. Record the length of the wire. Switch to Cell B by disconnecting Cell A and connecting Cell B in the same configuration. Rebalance the circuit by adjusting the wire length until the galvanometer again reads zero, and note the new length of the wire (L2). The ratio of L1 to L2 provides a comparative measure of the EMFs of the two cells.
