Respuesta :
Answer:
Explanation:
To find the molarity of the H2SO4 solution, we can follow these steps:
Calculate the moles of NaOH used:
Molarity (M) = moles of solute / volume of solution (L)
First, convert the volume of NaOH from cm³ to L: 38.70 cm³ * (1 L / 1000 cm³) = 0.0387 L
Now, calculate the moles of NaOH: moles of NaOH = M * V = 1.90 M * 0.0387 L = 0.07353
Relate moles of NaOH to moles of H2SO4:
Based on the balanced chemical equation for the neutralization reaction: 2 NaOH + H2SO4 -> 2 NaSO4 + 2 H2O
We see that 2 moles of NaOH react with 1 mole of H2SO4.
Therefore, the moles of H2SO4 neutralized are: moles of H2SO4 = moles of NaOH / 2 = 0.07353 / 2 = 0.036765
Calculate the molarity of H2SO4:
Molarity of H2SO4 = moles of H2SO4 / volume of H2SO4 solution (L)
Convert the volume of H2SO4 from cm³ to L: 10.30 cm³ * (1 L / 1000 cm³) = 0.0103 L
Finally, calculate the molarity: Molarity of H2SO4 = 0.036765 / 0.0103 L = 3.57 M
Therefore, the molarity of the H2SO4 solution is 3.57 M.
