I NEED HELP ASAP PLEASE!!! IT WOULD HELP SO MUCH :(
(Ill give u lots of points and brainiest :)

Answer:
x = 5, y = 6
Step-by-step explanation:
HL says that if the hypotenuse of two right triangles and one leg are congruent to each other, then the triangles are congruent. Therefore, we can write this as a system of equations:
x = y - 1 are the two congruent legs.
3x - 2 = 2y + 1 are the two congruent hypotenuses.
x = y - 1
Plug in y - 1 for x, and get:
3x - 2 = 2y + 1
3(y - 1) - 2 = 2y + 1
3y - 3 - 2 = 2y + 1
3y - 5 = 2y + 1
y - 5 = 1
y = 6
Plugging in 6 for y, we get:
x = 6 - 1
x = 5
Therefore, x = 5, and y = 6.
Step-by-step explanation:
Based on the congruency statement, we know that these two triangles are equal and one corresponding side is equal to the other. That means that side CB = DE and side AC = DA. Since these side values have equations attached to them, let's use a system of equations to solve for x and y.
Solving:
Given : side CB = DE and side AC = DA, [tex]x=y-1[/tex] and [tex]3x-2=2y+1[/tex]
Line up the system:
[tex]x=y-1[/tex]
[tex]3x-2=2y+1[/tex]
Substitute [tex]y-1[/tex] for [tex]x[/tex] in [tex]3x-2=2y+1[/tex]:
[tex]3(y-1)-2=2y+1[/tex]
Simplify:
[tex]3y-5=2y+1[/tex]
Subtract [tex]2y[/tex] from both sides :
[tex]3y-5-2y = 2y+1-2y[/tex]
Simplify:
[tex]y-5=1[/tex]
Add 5 to both sides:
[tex]y-5+5=1+5[/tex] → [tex]y=6[/tex]
Substitute 6 for [tex]y[/tex] in [tex]x=y-1[/tex]:
[tex]x=y-1[/tex]
[tex]x=(6)-1[/tex]
[tex]x=5[/tex]
Those are your two values, meaning the fourth option is correct.
That's it!