how many square tiles each of dimensions 2m x2m can be fixed on a vendha 2 m wide surrounding a rectangular room of length 20 m and breadth is 15 m

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Answer:

To determine the number of square tiles with dimensions 2m x 2m that can be fixed around a rectangular room, you need to find the perimeter of the room and then divide it by the area of each tile.

The perimeter (P) of the rectangular room is given by the formula:

\[ P = 2 \times (\text{length} + \text{breadth}) \]

For the given room with a length of 20m and a breadth of 15m:

\[ P = 2 \times (20 + 15) = 2 \times 35 = 70 \, \text{m} \]

Now, you want to surround the room with tiles, so the width of the surrounding is 2m on each side. Therefore, the effective perimeter for tiling is:

\[ \text{Effective Perimeter} = P + 2 \times (\text{width of surrounding}) \]

Substitute the values:

\[ \text{Effective Perimeter} = 70 + 2 \times 2 = 74 \, \text{m} \]

Now, find the area of each tile:

\[ \text{Area of each tile} = 2 \times 2 = 4 \, \text{m}^2 \]

Finally, calculate the number of tiles by dividing the effective perimeter by the area of each tile:

\[ \text{Number of tiles} = \frac{\text{Effective Perimeter}}{\text{Area of each tile}} \]

\[ \text{Number of tiles} = \frac{74}{4} = 18.5 \]

Therefore, approximately 18.5 square tiles with dimensions 2m x 2m can be fixed around the rectangular room. Note that you cannot have a fraction of a tile, so you would round down to 18 tiles.

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