Answer:
The volume expansion of a solid due to temperature change is governed by the coefficient of volumetric thermal expansion, which is a material property. This means that for a given material, the percentage increase in volume for a specific temperature change should be the same regardless of the initial volume or whether the object is solid or hollow. The formula for volumetric expansion is:
\[ \Delta V = V_0 \beta \Delta T \]
Where:
- \( \Delta V \) is the change in volume,
- \( V_0 \) is the initial volume,
- \( \beta \) is the coefficient of volumetric thermal expansion,
- \( \Delta T \) is the change in temperature.
Given that the material of the solid sphere and the hollow sphere is the same, and the temperature change (\( \Delta T \)) is the same for both, the percentage increase in volume due to thermal expansion will also be the same. This is because the coefficient of volumetric thermal expansion (\( \beta \)) is a property of the material and does not depend on the geometry of the object. Therefore, whether the sphere is solid or hollow does not affect the percentage increase in volume due to a given temperature increase.
So, the correct answer is:
b. Increases by 1%
Explanation: