Ariel needs to wrap 2 gifts with no overlap. The boxes are shaped as right rectangular prisms. The length of each box is 12.2 in, the
width is 5.2 in, and the height is 9 in. How much wrapping paper does Tiana need to buy?
Round your answer to the nearest hundredth.
in²

Respuesta :

msm555

Answer:

880.16 in²

Step-by-step explanation:

To find out how much wrapping paper Tiana needs to buy, we need to calculate the total surface area of the two boxes.

Each box has six faces: top, bottom, front, back, left side, and right side.

The surface area of one box is given by the formula:

[tex] \textsf{Surface Area} = 2lw + 2lh + 2wh [/tex]

Where:

  • [tex] l [/tex] is the length,
  • [tex] w [/tex] is the width, and
  • [tex] h [/tex] is the height of the box.

For the first box:

  • [tex] l = 12.2 [/tex] inches,
  • [tex] w = 5.2 [/tex] inches, and
  • [tex] h = 9 [/tex] inches.

Let's calculate the surface area for one box:

[tex] \textsf{Surface Area}_{\textsf{box 1}} = 2(12.2 \times 5.2) + 2(12.2 \times 9) + 2(5.2 \times 9) [/tex]

[tex] \textsf{Surface Area}_{\textsf{box 1}} = 2(63.44) + 2(109.8) + 2(46.8) [/tex]

[tex] \textsf{Surface Area}_{\textsf{box 1}} = 126.88 + 219.6 + 93.6 [/tex]

[tex] \textsf{Surface Area}_{\textsf{box 1}} = 440.08 \textsf{ square inches} [/tex]

Now, since Ariel needs to wrap two gifts, the total surface area of wrapping paper needed is:

[tex] \textsf{Total Surface Area} = 2 \times \textsf{Surface Area}_{\textsf{box 1}} [/tex]

[tex] \textsf{Total Surface Area} = 2 \times 440.08 [/tex]

[tex] \textsf{Total Surface Area} = 880.16 \textsf{ square inches} [/tex]

Tiana needs to buy 880.16 in² of wrapping paper.