Respuesta :
Answer:
2.45 m/s
Explanation:
we know that,
- Kinetic energy = ½ mv²
where
- m is mass of the body
- v is Velocity
we are given : A man of 50kg is moving at a constant velocity he has kinetic energy of 150J
substitute the given values in the above formula,
- 150 = 1/2 × 50 × v²
- 150 = 25 × v²
divide both sides by 25,
- v² = 6
squaring both sides
- v = 2.45 m/s
Therefore, the velocity at which he moves is 2.45 m/s.
Final answer:
The velocity of a 50 kg man who has a kinetic energy of 150J is approximately 2.45 m/s.
Explanation:
To calculate the velocity at which a 50 kg man moves, if he has a kinetic energy of 150J, we use the kinetic energy formula KE = (1/2)mv² where KE is kinetic energy, m is mass, and v is velocity. Rearranging this formula to solve for v, we get v = √(2KE/m). Plugging in the values, we have v = √(2*150J/50kg), which simplifies to v = √(6m²/s²). Thus, the velocity is the square root of 6 m/s which approximately equals 2.45 m/s.