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If 10.0 L of O₂ at standard conditions is compressed to a 7,000 mL container at -23.0°C, what is the new pressure?

Respuesta :

marblesan

Answer:

1.31 atm

Explanation:

Combined Gas Law

V1P1/T1 = V2P2/T2

Standard Conditions: P1 = 1 atm, T1 = 273.2 K

V1 = 10L

V2 = 7000mL = 7L

T2 = -23.0 C = 250.2 K

(10.0 * 1) / 273.2 = (7 * P) / 250.2

P = 1.31 atm (Rounded to sigfigs)

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