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PLEASE HURRY IT IS DUE SOON ignore the answer clicked on the picture. Line m passes through points (0, 0) and (1, 4). Line n passes through points (1, 1) and
(2, 4). Which system of equations could be solved to find the point where lines m and n
intersect?
O A.
O B.
O C.
O D.
y = 3x
= 2x
{√²3
y = 4x
y = 3x - 2
y = 4x + 1
y = 2x + 4
y = 4x + 4
y = 3x + 4

PLEASE HURRY IT IS DUE SOON ignore the answer clicked on the picture Line m passes through points 0 0 and 1 4 Line n passes through points 1 1 and 2 4 Which sys class=

Respuesta :

B. To calculate the slope, m(x) you have to find the distance. (0,0) (1,4) have a distance of x + 1 and y + 4. However y/x so the slope is 4x the y intercept (b) is what y is when x is 0, and at 0 x is 0 so there’s no 7 intercept. For the other one, apply this. (1,1)to (2,4) is x+1 and y+3. Y/X so 3/1. Slope is 3x and you want to put a y intercept where they will intersect. Therefore put it in point slope form. y-y1=m(x-x1)

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