The work shows the first steps of writing a partial fraction decomposition.
(3x+9)/(x+1)(x-5) = A/x+1 + B/x-5
3x+9=A(x-5)+B(x+1)
3x+9=Ax-5A+Bx+B

O (3x+9)/(x+1)(x-5) = 2/x+1 + 1/x-5
O (3x+9)/(x+1)(x-5) = 1/x+1 + 2/x-5
O (3x+9)/(x+1)(x-5) = (-1)/x+1 + 4/x-5
O (3x+9)/(x+1)(x-5) = 4/x+1 + (-1)/x-5