a and b→ are non-zero non-collinear vectors such that |a→|=2.|b→|=1 and angle between a¯ and b→ is π/3. If r→ is any vector satisfying r→.a¯=2,r¯.b¯=8.(r¯+2a¯−10b¯)⋅(a¯×b¯)=6 and r¯+2a¯−10b¯=�(a¯×b¯), then ⋋=
A. ½
B. 2
C. 4/√3