Consider a particle of constant mass m moving with velocity v in the xy-plane. Let r be the position vector of the particle relative to the origin O.
The angular momentum of the particle is the dot product of the position vector r and the linear momentum vector mv.
a) True
b) False

Respuesta :

Answer:

The statement is:

b) False

Explanation:

The angular momentum

[tex]\( \mathbf{L} \)[/tex]

of a particle relative to a fixed point

[tex](such as the origin \( O \))[/tex]

is indeed defined as the cross product of the position vector \

[tex]( \mathbf{r} \)[/tex]

and the linear momentum vector

[tex]\( \mathbf{p} = m\mathbf{v} \),[/tex]

not the dot product.

Mathematically, the angular momentum

[tex]\( \mathbf{L} \) is given by:[/tex]

[tex]\[ \mathbf{L} = \mathbf{r} \times \mathbf{p} \][/tex]

Where:

[tex]- \( \mathbf{L} \) is the angular momentum vector,[/tex]

[tex]- \( \mathbf{r} \) is the position vector from the origin to the particle,[/tex]

[tex]- \( \mathbf{p} \) is the linear momentum vector of the particle (which is mass \( m \) times velocity \( \mathbf{v} \)),[/tex]

[tex]- \( \times \) represents the cross product operation.[/tex]

So, the correct statement is that the angular momentum of the particle is the cross-product of the position vector

[tex]\( \mathbf{r} \)[/tex]

and the linear momentum vector

[tex]\( \mathbf{mv} \).[/tex]