Answer:
B) 30
Step-by-step explanation:
In quadrilateral ABCD, diagonals AC and BD are perpendicular bisectors of each other, indicating that ABCD is a rhombus.
In a rhombus, all sides are congruent, so AB ≅ BC ≅ CD ≅ AD.
Given that AB = 13, its follows that AD = 13.
As diagonals AC and DB bisect each other at point E, then AE ≅ EC.
Given that EC = 5, its follows that AE = 5.
The perimeter of triangle ADE is the sum of its side lengths:
Perimeter = AD + DE + AE
Perimeter = 13 + 12 + 5
Perimeter = 30
Therefore, the perimeter of ΔADE is 30 units.
