To find the equation of the axis of symmetry and the coordinates of the vertex of the function y = 2x^2 + 6x - 1, we can use the formula:
x = -b / (2a)
where a and b are the coefficients of the quadratic equation in the form ax^2 + bx + c.
In this case, a = 2 and b = 6. Substituting these values into the formula, we have:
x = -6 / (2 * 2)
x = -6 / 4
x = -1.5
So, the equation of the axis of symmetry is x = -1.5.
To find the y-coordinate of the vertex, we substitute the value of x = -1.5 into the original equation:
y = 2(-1.5)^2 + 6(-1.5) - 1
y = 2 * 2.25 - 9 - 1
y = 4.5 - 9 - 1
y = -5.5
Therefore, the coordinates of the vertex are (-1.5, -5.5).
The correct answer is b) x = -1.5; vertex: (-1.5, -5.5).
