Answer:
he correct answer is A. 112.
Explanation:
To find the mass of 2.11 × 10²⁴ sulfur atoms, we need to use the molar mass of sulfur (S), which is approximately 32.07 grams per mole (g/mol).
First, we find the number of moles of sulfur atoms:
[tex]\[ \text{Number of moles} = \frac{\text{Number of atoms}}{\text{Avogadro's number}} \][/tex]
[tex]\[ \text{Number of moles} = \frac{2.11 \times 10^{24}}{6.022 \times 10^{23}} \][/tex]
[tex]\[ \text{Number of moles} \approx 3.51 \][/tex]
Now, we use the molar mass of sulfur to find the mass:
[tex]\[ \text{Mass} = \text{Number of moles} \times \text{Molar mass} \][/tex]
[tex]\[ \text{Mass} = 3.51 \, \text{mol} \times 32.07 \, \text{g/mol} \][/tex]
[tex]\[ \text{Mass} \approx 112.9 \, \text{g} \][/tex]
Therefore, the mass of 2.11 × 10²⁴ sulfur atoms is approximately 112.9 grams.
The closest option provided is:
A. 112
So, the correct answer is A. 112.
