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When the shuttle bus comes to a sudden stop
to avoid hitting a dog, it decelerates uniformly
at 3.9 m/s2
as it slows from 8.8 m/s to 0 m/s.
Find the time interval of acceleration for
the bus.
Answer in units of s.

Respuesta :

Answer:

time = 2.26 s

Explanation:

Characteristic of Linear Motion with Constant Acceleration:

  • movement in a straight line
  • change in velocity in a steady rate
  • acceleration is constant

[tex]\boxed{\begin{array} vv=v_o+at\\\\s=s_o+v_ot+\frac{1}{2} at^2 \end{array}}[/tex]

v = final velocity

v₀ = initial velocity

a = acceleration

t = time

s = total distance

s₀ = initial distance

Given:

a = -3.9 m/s²

v₀ = 8.8 m/s

v = 0

Therefore,

[tex]\boxed{v=v_o+at}[/tex]

[tex]0=8.8+(-3.9)t[/tex]

[tex]3.9t=8.8[/tex]

[tex]t=\frac{8.8}{3.9}[/tex]

  [tex]\approx 2.26\ s[/tex]

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