✰Answer:
h^2 + 6h - 1 and 2h - 2 is 2h^3 + 10h^2 - 14h + 2
✰Step-by-step explanation:
The product of the polynomials h^2 + 6h - 1 and 2h - 2 can be found by using the distributive property of multiplication.
First, distribute 2h to each term in the first polynomial:
2h * (h^2 + 6h - 1) = 2h * h^2 + 2h * 6h + 2h * (-1)
This simplifies to:
2h^3 + 12h^2 - 2h
Next, distribute -2 to each term in the first polynomial:
-2 * (h^2 + 6h - 1) = -2 * h^2 - 2 * 6h - 2 * (-1)
This simplifies to:
-2h^2 - 12h + 2
Now, we can add the two simplified expressions together to find the product:
(2h^3 + 12h^2 - 2h) + (-2h^2 - 12h + 2) = 2h^3 + (12h^2 - 2h^2) + (-2h - 12h) + 2
This further simplifies to:
2h^3 + 10h^2 - 14h + 2
Therefore, the product of the polynomials h^2 + 6h - 1 and 2h - 2 is 2h^3 + 10h^2 - 14h + 2
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