Answer: 23.016 m/s
Step-by-step explanation:
To find the velocity of the skier when they reach the bottom of the hill, we can apply the law of conservation of energy, which states that energy cannot be created nor destroyed.
Therefore, the total gravitational potential energy of the skier has to be equal to the total kinetic energy of the skier.
The formula for gravitational potential energy (U) is given as:
U = mgh, where:
The formula for kinetic energy (K) is given as:
K = ½mv², where:
U = K
mgh = ½mv²
Let’s cancel the m’s on both sides:
gh = ½v²
Now, substitute the given values. We know that the acceleration due to gravity on Earth is 9.81 m/s², so g = 9.81. We are also given that the height of the hill is 27 m, so h = 27.
(9.81)(27) = ½v²
Solve for v:
264.87 = ½v²
529.74 = v²
v = 23.016
The velocity of the skier when they reach the bottom of the hill is 23.016 m/s.
Learn more about the law of conservation of energy here: brainly.com/question/166559
