Answer:
1-chloro-3,4-diethyl-1-methyl-6-propylcylcoheptane
Explanation:
The chlorine should have first naming priority because it's a halogen and the rest are alkyl groups, so you assign that a 1. You then want to number counterclockwise because that will give you the lowest number. There is a methyl attached to the 1 position so that gives you 1-methyl. The next group s are two ethyl groups at the 3 and 4 positions so you will name those 3,4-diethyl to show there are two of them. Lastly, there is a propyl group in the 6 position. Putting all together in alphabetical order would give you 1-chloro-3,4-diethyl-1-methyl-6-propylcylcoheptane
