ANSWER (REALLY) FAST 3
for some reason my mathxl loves putting this question in everything

write an equation in slope-intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation

(0,0);y = -4x + 2

jus simplify pls

Respuesta :

Answer:

y = [tex]\frac{1}{4}[/tex]x

Step-by-step explanation:

Given:

Perpendicular line: y = -4x + 2

m = -4

Pass through point (0,0).

Write an equation in slope-intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation.

For a line to be perpendicular to another line, the slopes of the two lines must be negative reciprocals.

m = -4 → m = [tex]\frac{1}{4}[/tex]

We use the point-slope form y - y₁ = m(x - x₁).

y - 0 = [tex]\frac{1}{4}[/tex](x - 0)

y = [tex]\frac{1}{4}[/tex]x

So, the equation is y = [tex]\frac{1}{4}[/tex]x.