Solve for k. J=k24 Responses ​k=±4J√​ ​, k equals plus or minus 4 root J end root, ​ k=±2J√J k equals plus or minus fraction numerator 2 root J end root over denominator J end fraction k=±4J k equals plus or minus 4 J k=±2J√ k equals plus or minus 2 root J end root
NEED ASAP

Respuesta :

To solve for k in the given equation, we have the following options:

1. k = ±4√J

2. k = ±2J√J

3. k = ±2√J/J

4. k = ±4J

5. k = ±2√J

Let's go through each option:

1. k = ±4√J:

In this case, k can take on two values: positive 4√J and negative 4√J.

2. k = ±2J√J:

Similarly, k can have two values: positive 2J√J and negative 2J√J.

3. k = ±2√J/J:

Here, k can be positive 2√J/J or negative 2√J/J.

4. k = ±4J:

For this option, k can be positive 4J or negative 4J.

5. k = ±2√J:

Finally, k can be positive 2√J or negative 2√J.

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