Respuesta :
Answer:
Let's address each part of the problem:
a) To calculate the net force acting on the stump, we need to find the horizontal and vertical components of the forces. The horizontal components of both ropes cancel each other out since they are in opposite directions. The vertical components add up. Using trigonometry, we can find that the vertical component of each force is 200 * sin(30°), so the total vertical force is:
\[ 2 \times 200 \times \sin(30°) = 400 \times \sin(30°) \]
\[ = 400 \times \frac{1}{2} = 200 \, \text{N} \]
So, the net force acting on the stump is 200 N vertically upward.
b) The tension in each rope is the same, as each rope exerts the same force. Therefore, the tension in each rope is 200 N.
c) Since the net force is vertically upward and the stump is on the ground, there must be an equal and opposite force of friction acting on the stump. This frictional force opposes the motion and prevents the stump from moving vertically.
d) The work done on the stump is the product of the force applied and the distance moved in the direction of the force. Since the stump doesn't move vertically due to the frictional force, the work done on it is zero.
So, to summarize:
a) Net force: 200 N vertically upward
b) Tension in each rope: 200 N
c) Frictional force: Equal to the net force, 200 N, acting downward
d) Work done on the stump: 0 J (Joules)
