Respuesta :
To find the equation of the straight line passing through points \(C(1,5)\) and \(D(3,9)\), we can use the point-slope form of the equation for a straight line:
\(y - y_1 = m(x - x_1)\)
where \(m\) is the slope of the line and \((x_1, y_1)\) is one of the given points.
First, let's find the slope (\(m\)) using the given points \(C\) and \(D\):
\(m = \frac{y_2 - y_1}{x_2 - x_1}\)
Substituting the given points:
\(m = \frac{9 - 5}{3 - 1} = \frac{4}{2} = 2\)
Now that we have the slope, let's choose point \(C(1,5)\) to substitute into the point-slope form:
\(y - 5 = 2(x - 1)\)
Now, we can simplify this equation:
\(y - 5 = 2x - 2\)
Add 5 to both sides:
\(y = 2x + 3\)
So, the equation of the straight line passing through points C(1,5) and D(3,9)is (y = 2x + 3).
\(y - y_1 = m(x - x_1)\)
where \(m\) is the slope of the line and \((x_1, y_1)\) is one of the given points.
First, let's find the slope (\(m\)) using the given points \(C\) and \(D\):
\(m = \frac{y_2 - y_1}{x_2 - x_1}\)
Substituting the given points:
\(m = \frac{9 - 5}{3 - 1} = \frac{4}{2} = 2\)
Now that we have the slope, let's choose point \(C(1,5)\) to substitute into the point-slope form:
\(y - 5 = 2(x - 1)\)
Now, we can simplify this equation:
\(y - 5 = 2x - 2\)
Add 5 to both sides:
\(y = 2x + 3\)
So, the equation of the straight line passing through points C(1,5) and D(3,9)is (y = 2x + 3).
Answer:
[tex]\sf y = 2x + 3[/tex]
Step-by-step explanation:
To find the equation of the straight line passing through points [tex]\sf C(1,5)[/tex] and [tex]\sf D(3,9)[/tex], we can use the point-slope form of the equation of a line:
[tex]y - y_1 = m(x - x_1)[/tex]
where
- [tex]\sf m[/tex] is the slope of the line, and
- [tex]\sf (x_1, y_1)[/tex] is a point on the line.
First, let's find the slope ([tex]\sf m[/tex]) using the coordinates of points [tex]\sf C[/tex] and [tex]\sf D[/tex]:
[tex]m = \dfrac{{y_2 - y_1}}{{x_2 - x_1}}[/tex]
where [tex]\sf x_1 = 1[/tex], [tex]\sf y_1 = 5[/tex], [tex]\sf x_2 = 3[/tex], and [tex]\sf y_2 = 9[/tex].
[tex]m = \dfrac{{9 - 5}}{{3 - 1}} = \dfrac{4}{2} = 2[/tex]
Now that we have the slope, let's choose one of the points, say [tex]\sf C(1,5)[/tex], and substitute the coordinates and the slope into the point-slope form:
[tex]y - 5 = 2(x - 1)[/tex]
Now, we can simplify and rewrite the equation in slope-intercept form ([tex]\sf y = mx + b[/tex]):
[tex]y - 5 = 2x - 2[/tex]
[tex]y = 2x - 2 + 5[/tex]
[tex]y = 2x + 3[/tex]
So, the equation of the straight line passing through points [tex]\sf C(1,5)[/tex] and [tex]\sf D(3,9)[/tex] is:
[tex]\sf y = 2x + 3[/tex]