Answer:
The balanced chemical equation for the reaction between Fe₂O₃ and H₂SO₄ is:
Fe₂O₃ + 3H₂SO₄ → Fe₂(SO₄)₃ + 3H₂O
Molar mass of Fe₂O₃ = 159.69 g/mol
Molar mass of H₂SO₄ = 98.08 g/mol
1.273 g Fe₂O₃ * (1 mol Fe₂O₃ / 159.69 g Fe₂O₃) * (3 mol H₂SO₄ / 1 mol Fe₂O₃) * (1 L / 1.38 mol H₂SO₄) * (1000 mL / 1 L) = 27.84 mL
Explanation:
First, find the moles of Fe₂O₃ using its molar mass. Then, use the stoichiometry of the balanced equation to convert moles of Fe₂O₃ to moles of H₂SO₄. Finally, convert moles of H₂SO₄ to milliliters using its molarity.
