Answer:
154 mL of 0.213 M HCL(aq) must be diluted to make 491.1 mL of 0.0669 M HCL(aq).
Explanation:
To dilute the HCL(aq) to a lower concentration, we can use the formula:
M1V1 = M2V2
Given: M1 = 0.213 M, V1 = unknown, M2 = 0.0669 M, V2 = 491.1 mL = 0.4911L
Plugging in the values: (0.213 M)(V1) = (0.0669 M)(0.4911 L)
Solving for V1: V1 = (0.0669 M)(0.4911 L) / 0.213 M
Calculating V1: V1 = 0.154 L = 154 mL
Therefore, 154 mL of 0.213 M HCL(aq) must be diluted to make 491.1 mL of 0.0669 M HCL(aq). This is because the moles of the solute remain constant before and after dilution, allowing us to use the dilution formula to find the volume needed for the desired concentration.
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