A solution is obtained by mixing 200 g of a 30% and 300 g of a 20% solution by weight. The percentage of solute in the final solution will be:
A) 22%
B) 24%
C) 25%
D) 26%

Respuesta :

Answer: B) 24%

Step-by-step explanation:

In order to solve this problem, we must find the individual masses using the percentages from both solutions. From there we add them together and divide by their total weights in order to find percentage of solute.

Solving:

[tex]m_1 = \frac{30}{100} \times 200 = \boxed{60 \text{ grams}} \\m_2 = \frac{20}{100} \times 300 = \boxed{60 \text{ grams}} \\\\\text{Total amount of solute} = 60 + 60 = 120 \text{ grams} \\\text{Total weight of solution} = 200 + 300 = 500 \text{ grams} \\\\\\[/tex]

Now that we have the solution weight and the total weight, divide them together to get the percentage of solute.

[tex]\text{Percentage of solute in the final solution} : \frac{\text{Total amount of solute}}{\text{Total weight of solution}} \times 100\\[/tex]

[tex]\text{Percentage of solute in the final solution} = \frac{120}{500} \times 100 =\boxed{ 24\%}[/tex]

Therefore, The percentage of solute in the final solution will be: 24%

Final answer:

The percentage of the final solution is 24%.

C) 25%

Explanation:

The percentage of the final solution is 24%.

  1. Calculate the total mass of the final solution: 200 g + 300 g = 500 g
  2. Calculate the total mass of the solute in the final solution: (0.3 * 200 g) + (0.2 * 300 g) = 60 g + 60 g = 120 g
  3. Calculate the percentage of the solute in the final solution: (120 g / 500 g) * 100% = 24%