Given: Cr3+(aq)+3e- ⇌Cr(s);E°=−0.74V Cl2(g)+2e- ⇌2Cl−(aq);E°=1.36V What is the standard Gibbs free-energy change for the following reaction? (F = 96485 C per mole of electrons). 2Cr(s) +3Cl2(g) ⇔2Cr3+(aq) +6Cl−(aq)
a) -140.38 kJ/mol
b) -83.88 kJ/mol
c) 140.38 kJ/mol
d) 83.88 kJ/mol