In Casino Del Rio, a gambler can bet in whole dollars. Each bet will either gain $1 with a probability of 0. 4 or lose $1 with a probability of 0. 6.
a) $0. 40
b) $0. 60
c) $1. 00
d) -$1. 00

Respuesta :

To find the expected value of a single bet in Casino Del Rio, we use the formula:

\[ E(X) = (Gain_1 \times P(Gain_1)) + (Gain_2 \times P(Gain_2)) \]

Where:

- \( E(X) \) is the expected value,

- \( Gain_1 \) is the gain if the bet wins,

- \( P(Gain_1) \) is the probability of winning,

- \( Gain_2 \) is the loss if the bet loses,

- \( P(Gain_2) \) is the probability of losing.

Given:

- \( Gain_1 = \$1 \),

- \( P(Gain_1) = 0.4 \),

- \( Gain_2 = -\$1 \),

- \( P(Gain_2) = 0.6 \).

Substituting the given values into the formula:

\[ E(X) = (\$1 \times 0.4) + ((-\$1) \times 0.6) \]

\[ E(X) = \$0.40 - \$0.60 \]

\[ E(X) = -\$0.20 \]

The expected value of a single bet in Casino Del Rio is -$0.20.

However, since the options provided are in whole dollars, we round this value to the nearest whole dollar, which is -$1.00.

Therefore, the correct answer is:

d) -$1.00