Line v has an equation of y=8x+2. Line w is parallel to line v and passes through (–
1,–
2). What is the equation of line w?
Write the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.

Respuesta :

Answer:

y = 8x + 6

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given line v with equation

y = 8x + 2 ← in slope- intercept form

with slope m = 8

Parallel lines have equal slopes , then

y = 8x + c ← is the partial equation

to find c, substitute (- 1, - 2 ) for x and y in the partial equation

- 2 = 8(- 1) + c = - 8 + c ( add 8 to both sides )

6 = c

y = 8x + 6 ← equation of line w

msm555

Answer:

[tex] y = 8x + 6 [/tex]

Step-by-step explanation:

Lines that are parallel have the same slope. The equation of line v is [tex]y = 8x + 2[/tex], where the slope ([tex]m_v[/tex]) is 8 while comparing with y = mx + c.

Since line w is parallel to line v, it will also have a slope of 8. Now, we can use the point-slope form of a linear equation to find the equation of line w. The point-slope form is given by:

[tex] y - y_1 = m(x - x_1) [/tex]

where [tex](x_1, y_1)[/tex] is a point on the line and [tex]m[/tex] is the slope.

For line w, with a point [tex](-1, -2)[/tex] and a slope of 8, the equation becomes:

[tex] y - (-2) = 8(x - (-1)) [/tex]

Simplify this equation:

[tex] y + 2 = 8(x + 1) [/tex]

Distribute the 8:

[tex] y + 2 = 8x + 8 [/tex]

Now, isolate [tex]y[/tex]:

[tex] y = 8x + 8 - 2 [/tex]

Combine constants:

[tex] y = 8x + 6 [/tex]

So, the equation of line w in slope-intercept form is:

[tex]y = 8x + 6[/tex]