Answer:
Pressure of the gas when the volume is decreased to 2.62 L: 328 atm
Explanation:
Use Boyle's Law, which states that for a given amount of gas at constant temperature, the pressure and volume are inversely proportional.
P1V1 = P2V2
Where:
P1 = initial pressure (147 atm)
V1 = initial volume (5.90 L)
P2 = final pressure (what we want to find)
V2 = final volume (2.62 L)
Plug in the given values into the equation:
147 atm * 5.90 L = P2 * 2.62 L
Solve for P2:
P2 = (147 atm * 5.90 L) / 2.62 L
P2 = (867.3) / 2.62 atm
P2 ≈ 330.69 atm
Round the answer to the appropriate number of significant figures:
P2 ≈ 328 atm
So, the pressure of the gas when the volume is decreased to 2.62 L is approximately 328 atm.
