Answer: There are approximately 0.199 moles of silver (Ag) in 46.2 grams of silver oxide (Ag2O).
Explanation:
To find the number of moles of silver (Ag) in 46.2 grams of silver oxide (Ag2O), we first need to determine the molar mass of Ag2O and then use it to convert grams to moles.
Calculate the molar mass of Ag2O:
The molar mass of Ag = 107.87 g/mol (from the periodic table)
The molar mass of O = 16.00 g/mol (from the periodic table)
The molar mass of Ag2O = (2 * molar mass of Ag) + molar mass of O
= (2 * 107.87 g/mol) + 16.00 g/mol
= 215.74 g/mol + 16.00 g/mol
= 231.74 g/mol
Now, use the molar mass to convert grams to moles:
Moles of Ag2O = Mass / Molar mass
= 46.2 g / 231.74 g/mol
≈ 0.199 moles
Therefore, there are approximately 0.199 moles of silver (Ag) in 46.2 grams of silver oxide (Ag2O).
