contestada

What is the equation of the circle graphed below?
answer choices:

\large \left(x+3\right)^2+\left(y-4\right)^2=4

b
\large \left(x-3\right)^2+\left(y+4\right)^2=4

c
\large \left(x+3\right)^2+\left(y-4\right)^2=16

d
\large \left(x-3\right)^2+\left(y+4\right)^2=16

What is the equation of the circle graphed below answer choices large leftx3right2lefty4right24 b large leftx3right2lefty4right24 c large leftx3right2lefty4righ class=

Respuesta :

Answer:

The correct answer is D. (x-3)² + (y+4)² = 16

Step-by-step explanation:

Equation of a Circle with Center (a, b) and Radius r:

[tex]\boxed{(x-a)^2+(y-b)^2=r^2}[/tex]

To find the center of a circle:

  1. Draw a square around the circle.
  2. The center is the intersection point of the square's diagonals.

From the picture, we can find that the Center is (3, -4) and the Radius is 4 units. Therefore the Equation of the circle:

[tex](x-a)^2+(y-b)^2=r^2[/tex]

[tex](x-3)^2+(y-(-4))^2=4^2[/tex]

[tex]\bf(x-3)^2+(y+4)^2=16[/tex]

Ver imagen karmenchong

Otras preguntas