Answer:
There are 27.24 grams
Explanation:
The balanced chemical equation for the conversion of NO to NO2 is:
2 NO(g) + O2(g) → 2 NO2(g)
This means that for every 2 moles of NO, we produce 2 moles of NO2.
Given that we have 0.592 moles of NO, the amount of NO2 produced will be twice this amount:
0.592 moles of NO * (2 moles of NO2 / 2 moles of NO) = 0.592 moles of NO2
Now, we'll convert moles of NO2 to grams using the molar mass of NO2:
Molar mass of NO2 = 14.01 (N) + 2 * 16.00 (O) = 14.01 + 32.00 = 46.01 g/mol
Mass of NO2 = moles of NO2 * molar mass of NO2 Mass of NO2 = 0.592 moles * 46.01 g/mol Mass of NO2 ≈ 27.24 grams
So, there are approximately 27.24 grams of NO2 gas in 16.0 liters of NO at STP.
