Answer:
To solve this, let's break down the probabilities for each shooter:
i. To find the probability that only two shots hit the target:
For Mr. A: Probability of hitting 2 shots out of 5.
For Mr. B: Probability of hitting 2 shots out of 4.
For Mr. C: Probability of hitting 2 shots out of 5.
ii. To find the probability that only one shot hits the target:
For Mr. A: Probability of hitting 1 shot out of 5.
For Mr. B: Probability of hitting 1 shot out of 4.
For Mr. C: Probability of hitting 1 shot out of 5.
Let's calculate each:
i. Probability of only two shots hitting the target:
For Mr. A: \( \frac{{\binom{5}{2}}}{{5^2}} \)
For Mr. B: \( \frac{{\binom{4}{2}}}{{4^2}} \)
For Mr. C: \( \frac{{\binom{5}{2}}}{{5^2}} \)
Now, sum up the individual probabilities for each shooter to get the total probability for i.
ii. Probability of only one shot hitting the target:
For Mr. A: \( \frac{{\binom{5}{1}}}{{5^1}} \)
For Mr. B: \( \frac{{\binom{4}{1}}}{{4^1}} \)
For Mr. C: \( \frac{{\binom{5}{1}}}{{5^1}} \)
Again, sum up the individual probabilities for each shooter to get the total probability for ii.