2x^3-9x^2+7x+6=0
Solve

Answer:
x = - [tex]\frac{1}{2}[/tex], 2, 3
Step-by-step explanation:
2x³ - 9x² + 7x + 6 = 0
Factor using the rational roots test.
(2x + 1) (x² - 5x + 6) = 0
(2x + 1) (x - 3) (x - 2) = 0
2x + 1 = 0
x = - [tex]\frac{1}{2}[/tex]
x - 3 = 0
x = 3
x - 2 = 0
x = 2
So, x = - [tex]\frac{1}{2}[/tex], 2, 3