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For ethanol, C2H5OH,
Specific heat
Solid 111 J / (mol K)
Melting point - 114 C
Boiling point 78.4 °C
delta H (fusion) 4.97 kJ./ mol
delta H (vaporization) 42.3 kJ / mol
Liquid = 2.43 J / (g K)
Gas 1.70 J/ (g K)
How much heat would be needed to change 10.0 g ethanol at 21.0 °C to 115 °C

Respuesta :

J

K

1

m

o

l

1

We are given that,

H

v

a

p

=

42.4

k

J

m

o

l

1

,

T

=

273

+

78.4

=

351.4

K

We know that,

S

v

a

p

=

H

v

a

p

T

putting the values,

=

42.4

×

10

3

351.4

=

120.66

J

K

1

m

o

l

1

Theory:

Entropy Calculation with phase transformation:

Phase change occurs at constant Pressure & Temperature and is considered reversible if it occurs at its transition temperature.

Entropy change for Vaporisation:

At constant pressure,

q

=

q

p

=

Δ

H

Δ

S

v

a

p

=

Δ

H

v

a

p

T

b

where

T

b

is boiling point of a substance.