Answer:
Sure, let's solve them one by one:
1. \( \frac{2x}{3} + 9 = 25 \)
Subtract 9 from both sides:
\( \frac{2x}{3} = 25 - 9 \)
\( \frac{2x}{3} = 16 \)
Multiply both sides by 3:
\( 2x = 16 \times 3 \)
\( 2x = 48 \)
Divide both sides by 2:
\( x = \frac{48}{2} \)
\( x = 24 \)
2. \( 5x + 6 = 3x + 18 \)
Subtract 3x from both sides:
\( 5x - 3x + 6 = 18 \)
\( 2x + 6 = 18 \)
Subtract 6 from both sides:
\( 2x = 18 - 6 \)
\( 2x = 12 \)
Divide both sides by 2:
\( x = \frac{12}{2} \)
\( x = 6 \)
3. \( 9x - 12 = 3x + 18 \)
Subtract 3x from both sides:
\( 9x - 3x - 12 = 18 \)
\( 6x - 12 = 18 \)
Add 12 to both sides:
\( 6x = 18 + 12 \)
\( 6x = 30 \)
Divide both sides by 6:
\( x = \frac{30}{6} \)
\( x = 5 \)
4. \( 3(x - 4) = 9 \)
Distribute the 3:
\( 3x - 12 = 9 \)
Add 12 to both sides:
\( 3x = 9 + 12 \)
\( 3x = 21 \)
Divide both sides by 3:
\( x = \frac{21}{3} \)
\( x = 7 \)
5. \( \frac{x}{2} - 3 = 4 \)
Add 3 to both sides:
\( \frac{x}{2} = 4 + 3 \)
\( \frac{x}{2} = 7 \)
Multiply both sides by 2:
\( x = 7 \times 2 \)
\( x = 14 \)
